electrochemistry
Since I only had sulfuric acid and lead electrodes, I decided to firstly run 2 lead electrodes through electrolysis in a sulfuric acid electrolyte. This would create the following half equations: $$ce{4H+ + 4e- -> 2H2}$$ $$ce{Pb +2H2O->PbO2 +4H+ +4e-}$$ At this stage, I still need to perform some theoretical calculations of the required ...